Math delimiters

Inline math

• Render $x = 1$ as $x = 1$.
• Render \\( x = 2 \\) as \( x = 2 \).
• Render \(x = 3\) as (x = 3). Fails because of Common Mark escaped punctuation.

Full line math

Render $$ x = 6$$:

$$ x = 6$$

Render \\[x = 4\\]:

\[x = 4\]

Render \[x = 5\]:

[x = 5]

Fails because of Common Mark escaped punctuation.

Environments

First align:

\begin{align} x&=2 \\ y&=3 \end{align}

Then align*:

\begin{align*} x&=2 \\ y&=3 \end{align*}

Finally aligned:

$$ \begin{aligned} x&=2 \\ y&=3 \end{aligned} $$

Labels and references

\begin{equation} \label{eq_four} 4 + 4 \not= 4\,. \end{equation}

See equation $\eqref{eq_four}$.

• Not working in KaTex open issue.

Set notation

• Render $S:=\\{1, 2, \dotsc, 10\\}$ as $S:=\{1, 2, \dotsc, 10\}$.
• Render $S:=\lbrace{}1, 2, \dotsc, 10\rbrace{}$ as $S:=\lbrace{}1, 2, \dotsc, 10\rbrace{}$.
• Render $S:=\lbrace1, 2, \dotsc, 10\rbrace$ as $S:=\lbrace1, 2, \dotsc, 10\rbrace$. Works only because first set element starts with digit.
• Render $S:=\{1, 2, \dotsc, 10\}$ as $S:={1, 2, \dotsc, 10}$. Fails because of Common Mark escaped punctuation.

Spacing

• Render $A\qquad{}A\quad{}A\\,A\\:A\\;A\\!A$ as $A\qquad{}A\quad{}A\,A\:A\;A\!A$.

Subscripts

• Render $A_i$ as $A_i$.
• Render $(A_i)_{i\in{}I}$ as $(A_i)_{i\in{}I}$. This fails because Markdown emphasizes with _.
• Render $(A\_i)\_{i\in{}I}$ as $(A_i)_{i\in{}I}$.
• Render $(A\_i)_{i\in[n]}$ as $(A_i)_{i\in[n]}$.
• Render $(\delta_i)_{i\in[n]}$ as $(\delta_i)_{i\in[n]}$.
• Render $(\delta_i)_{i\in[n]}$ are $\delta_i:=x_i-x_{i-1}>0$ as $(\delta_i){i\in[n]}$ are $\delta_i:=x_i-x{i-1}>0$.
  • Failing because too many _ within context clashing with markdown italtics.
• Render $(\delta\_i)_{i\in[n]}$ are $\delta_i:=x_i-x_{i-1}>0$ as $(\delta_i){i\in[n]}$ are $\delta_i:=x_i-x{i-1}>0$.
  • Failing because too many _ within context clashing with markdown italtics.
• Render $(\delta_i)\_{i\in[n]}$ are $\delta_i:=x_i-x_{i-1}>0$ as $(\delta_i)_{i\in[n]}$ are $\delta_i:=x_i-x_{i-1}>0$.
• Render $(\delta\_i)\_{i\in[n]}$ are $\delta_i:=x_i-x_{i-1}>0$ as $(\delta_i)_{i\in[n]}$ are $\delta_i:=x_i-x_{i-1}>0$.

Definitions

New command

How to do in mathjax

$\newcommand{\NN}{\mathbb{N}}$

Let $x\in\NN$.

$\newcommand{\NN}{\mathbb{N}}$

Let $x\in\NN$.